PHP 8.3.0 RC 6 available for testing

strpbrk

(PHP 5, PHP 7, PHP 8)

strpbrk在字符串中查找一组字符的任何一个字符

说明

strpbrk(string $string, string $characters): string|false

strpbrk()string 字符串中查找 characters

参数

string

在此字符串中查找 string

characters

该参数区分大小写。

返回值

返回以找到的字符开始的子字符串。如果没有找到,则返回 false

示例

示例 #1 strpbrk() 示例

<?php

$text
= 'This is a Simple text.';

// 输出 "is is a Simple text.",因为 'i' 先被匹配
echo strpbrk($text, 'mi');

// 输出 "Simple text.",因为字符区分大小写
echo strpbrk($text, 'S');
?>

参见

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User Contributed Notes 2 notes

up
10
devnuhl
9 years ago
If you're not looking to duplicate the rest of the string, but instead just want the offset, in the spirit of the str*pos() functions, use strcspn()
up
6
guillaume dot barranco at free dot fr
6 years ago
A little modification to Evan's code to use an array for the second parameter :

<?php

function strpbrkpos($s, $accept) {
$r = FALSE;
$t = 0;
$i = 0;
$accept_l = count($accept);

for ( ;
$i < $accept_l ; $i++ )
if ( (
$t = strpos($s, $accept[$i])) !== FALSE )
if ( (
$r === FALSE) || ($t < $r) )
$r = $t;

return
$r;
}

?>
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