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similar_text

(PHP 4, PHP 5, PHP 7, PHP 8)

similar_text计算两个字符串的相似度

说明

similar_text(string $string1, string $string2, float &$percent = null): int

两个字符串的相似程度计算依据 Programming Classics: Implementing the World's Best Algorithms by Oliver (ISBN 0-131-00413-1) 的描述进行。注意该实现没有使用 Oliver 虚拟码中的堆栈,但是却进行了递归调用,这个做法可能会导致整个过程变慢或变快。也请注意,该算法的复杂度是 O(N**3),N 是最长字符串的长度。

参数

string1

第一个字符串。

string2

第二个字符串。

注意:

交换 string1string2 可能会产生不同的结果;请看下面的示例。

percent

第三个参数通过引用传递,similar_text() 将以百分比计算相似度,通过将 similar_text() 的结果除以指定字符串长度的平均值然后乘以 100

返回值

返回在两个字符串中匹配字符的数量。

The number of matching characters is calculated by finding the longest first common substring, and then doing this for the prefixes and the suffixes, recursively. The lengths of all found common substrings are added.

示例

示例 #1 similar_text() 交换参数示例

此示例展示了交换 string1string2 可能会产生不同的结果。

<?php
$sim
= similar_text('bafoobar', 'barfoo', $perc);
echo
"similarity: $sim ($perc %)\n";
$sim = similar_text('barfoo', 'bafoobar', $perc);
echo
"similarity: $sim ($perc %)\n";

以上示例的输出类似于:

 
similarity: 5 (71.428571428571 %)
similarity: 3 (42.857142857143 %)

参见

  • levenshtein() - 计算两个字符串之间的 Levenshtein 距离
  • soundex() - Calculate the soundex key of a string

add a note

User Contributed Notes 11 notes

up
108
SPAM HATER
11 years ago
Hey there,

Be aware when using this function, that the order of passing the strings is very important if you want to calculate the percentage of similarity, in fact, altering the variables will give a very different result, example :

<?php
$var_1
= 'PHP IS GREAT';
$var_2 = 'WITH MYSQL';

similar_text($var_1, $var_2, $percent);

echo
$percent;
// 27.272727272727

similar_text($var_2, $var_1, $percent);

echo
$percent;
// 18.181818181818
?>
up
93
daniel dot karbach at localhorst dot tv
12 years ago
Please note that this function calculates a similarity of 0 (zero) for two empty strings.

<?php
similar_text
("", "", $sim);
echo
$sim; // "0"
?>
up
22
I_HATE_SPAMMER- PAZ!
9 years ago
Actually similar_text() is not bad...
it works good. But before processing i think is a good way to make a little mod like this

$var_1 = strtoupper("doggy");
$var_2 = strtoupper("Dog");

similar_text($var_1, $var_2, $percent);

echo $percent; // output is 75 but without strtoupper output is 50
up
19
ryan at derokorian dot com
9 years ago
Note that this function is case sensitive:

<?php

$var1
= 'Hello';
$var2 = 'Hello';
$var3 = 'hello';

echo
similar_text($var1, $var2); // 5
echo similar_text($var1, $var3); // 4
up
15
vasyl at vasyltech dot com
7 years ago
Recursive algorithm usually is very elegant one. I found a way to get better precision without the recursion. Imagine two different (or same) length ribbons with letters on each. You simply shifting one ribbon to left till it matches the letter the first.

<?php

function similarity($str1, $str2) {
$len1 = strlen($str1);
$len2 = strlen($str2);

$max = max($len1, $len2);
$similarity = $i = $j = 0;

while ((
$i < $len1) && isset($str2[$j])) {
if (
$str1[$i] == $str2[$j]) {
$similarity++;
$i++;
$j++;
} elseif (
$len1 < $len2) {
$len1++;
$j++;
} elseif (
$len1 > $len2) {
$i++;
$len1--;
} else {
$i++;
$j++;
}
}

return
round($similarity / $max, 2);
}

$str1 = '12345678901234567890';
$str2 = '12345678991234567890';

echo
'Similarity: ' . (similarity($str1, $str2) * 100) . '%';
?>
up
1
pablo dot pazos at cabolabs dot com
2 years ago
To calculate the percentage of similarity between two strings without depending on the order of the parameters and be case insensitive, I use this function based on levenshtein's distance:

<?php

// string similarity calculated using levenshtein
static function similarity($a, $b)
{
return
1 - (levenshtein(strtoupper($a), strtoupper($b)) / max(strlen($a), strlen($b)));
}

?>

This will always return a number between 0 and 1, representing the percentage, for instance 0.8 represents 80% similar strings.

If you want this to be case-sensitive, just remove the strtoupper() functions.
up
9
daniel at reflexionsdesign dot com
22 years ago
If performance is an issue, you may wish to use the levenshtein() function instead, which has a considerably better complexity of O(str1 * str2).
up
11
Paul
16 years ago
The speed issues for similar_text seem to be only an issue for long sections of text (>20000 chars).

I found a huge performance improvement in my application by just testing if the string to be tested was less than 20000 chars before calling similar_text.

20000+ took 3-5 secs to process, anything else (10000 and below) took a fraction of a second.
Fortunately for me, there was only a handful of instances with >20000 chars which I couldn't get a comparison % for.
up
12
julius at infoguiden dot no
20 years ago
If you have reserved names in a database that you don't want others to use, i find this to work pretty good.
I added strtoupper to the variables to validate typing only. Taking case into consideration will decrease similarity.

<?php
$query
= mysql_query("select * from $table") or die("Query failed");

while (
$row = mysql_fetch_array($query)) {
similar_text(strtoupper($_POST['name']), strtoupper($row['reserved']), $similarity_pst);
if (
number_format($similarity_pst, 0) > 90){
$too_similar = $row['reserved'];
print
"The name you entered is too similar the reserved name &quot;".$row['reserved']."&quot;";
break;
}
}
?>
up
3
georgesk at hotmail dot com
21 years ago
Well, as mentioned above the speed is O(N^3), i've done a longest common subsequence way that is O(m.n) where m and n are the length of str1 and str2, the result is a percentage and it seems to be exactly the same as similar_text percentage but with better performance... here's the 3 functions i'm using..

<?php
function LCS_Length($s1, $s2)
{
$m = strlen($s1);
$n = strlen($s2);

//this table will be used to compute the LCS-Length, only 128 chars per string are considered
$LCS_Length_Table = array(array(128),array(128));


//reset the 2 cols in the table
for($i=1; $i < $m; $i++) $LCS_Length_Table[$i][0]=0;
for(
$j=0; $j < $n; $j++) $LCS_Length_Table[0][$j]=0;

for (
$i=1; $i <= $m; $i++) {
for (
$j=1; $j <= $n; $j++) {
if (
$s1[$i-1]==$s2[$j-1])
$LCS_Length_Table[$i][$j] = $LCS_Length_Table[$i-1][$j-1] + 1;
else if (
$LCS_Length_Table[$i-1][$j] >= $LCS_Length_Table[$i][$j-1])
$LCS_Length_Table[$i][$j] = $LCS_Length_Table[$i-1][$j];
else
$LCS_Length_Table[$i][$j] = $LCS_Length_Table[$i][$j-1];
}
}
return
$LCS_Length_Table[$m][$n];
}

function
str_lcsfix($s)
{
$s = str_replace(" ","",$s);
$s = ereg_replace("[��������]","e", $s);
$s = ereg_replace("[������������]","a", $s);
$s = ereg_replace("[��������]","i", $s);
$s = ereg_replace("[���������]","o", $s);
$s = ereg_replace("[��������]","u", $s);
$s = ereg_replace("[�]","c", $s);
return
$s;
}

function
get_lcs($s1, $s2)
{
//ok, now replace all spaces with nothing
$s1 = strtolower(str_lcsfix($s1));
$s2 = strtolower(str_lcsfix($s2));

$lcs = LCS_Length($s1,$s2); //longest common sub sequence

$ms = (strlen($s1) + strlen($s2)) / 2;

return ((
$lcs*100)/$ms);
}
?>

you can skip calling str_lcsfix if you don't worry about accentuated characters and things like that or you can add up to it or modify it for faster performance, i think ereg is not the fastest way?
hope this helps.
Georges
up
-1
Anonymous
3 years ago
$result = similar_text ('ab', 'a', $percent);

> $percent: 66.666666666666671
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