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    ReflectionMethod::invokeArgs

    (PHP 5 >= 5.1.2, PHP 7, PHP 8)

    ReflectionMethod::invokeArgs — 带参数执行

    说明

    public ReflectionMethod::invokeArgs(?object $object, array $args): mixed

    使用数组给方法传送参数，并执行他。

    参数

    object

    调用方法的对象，如果是静态对象，设置为 null

    args

    使用 array 传送的方法参数。

    返回值

    返回方法返回值。

    错误／异常

    如果 object 指定的实例无法执行方法，那么产生 ReflectionException 异常。

    如果方法调用失败，产生 ReflectionException

    更新日志

    版本 说明
    8.0.0 args 的键现在将解释为参数的名称，而不是默默忽略。

    示例

    示例 #1 ReflectionMethod::invokeArgs() 示例

    <?php
    class HelloWorld {

    public function     sayHelloTo($name) {
    return     'Hello ' . $name;
    }

    }

    $reflectionMethod = new ReflectionMethod('HelloWorld', 'sayHelloTo');
    echo     $reflectionMethod->invokeArgs(new HelloWorld(), array('Mike'));
    ?>

    以上示例会输出：

     
Hello Mike

    注释

    注意:

    如果函数有参数需为引用，那么它们必须以引用方式传入。

    参见

    ＋add a note

    User Contributed Notes 4 notes

    up
    12
    serg dot smertin at gmail dot com
    13 years ago
    We can do black magic, which is useful in templating block calls:

    <?php
    $object    ->__named('methodNameHere', array('arg3' => 'three', 'arg1' => 'one'));

    ...

    /**
    * Pass method arguments by name
    *
    * @param string $method
    * @param array $args
    * @return mixed
    */
    public function __named($method, array $args = array())
    {
    $reflection = new ReflectionMethod($this, $method);

    $pass = array();
    foreach(    $reflection->getParameters() as $param)
    {
    /* @var $param ReflectionParameter */
    if(isset($args[$param->getName()]))
    {
    $pass[] = $args[$param->getName()];
    }
    else
    {
    $pass[] = $param->getDefaultValue();
    }
    }

    return     $reflection->invokeArgs($this, $pass);
    }
    ?>
    up
    4
    agent_harris at secure-mail dot biz
    12 years ago
    There is a simple workaround for the reference passing problem:
    Since the reflection api has to handle all parameters in a generic way it has no chance to guess if you wish to pass data per value or reference.

    But it seems that you can also decide to pass a reference from where you call the function or method (not just only by the ampersand prefix in its declaration).

    So just do the following; which worked for me:

    <?php
    //...
    $method->invoke($object, $inputValue, &$outputValue);
    ?>

    Since this will only be necessary with arrays and primitive data types it should be acceptable in most cases to know in advance if you need to pass per reference. But it is probably although necessary to keep the ampersand always in the declaration (because of the at least two layers between the actual function and your invoke call).

    If this is the expected behavior it will maybe make sense to mention it in the documentation for invoke and invokeArgs.
    up
    2
    CodeCoutureXX at gmail dot com
    8 years ago
    If you need to call ReflectionMethod::invokeArgs() on a static function you can pass NULL in for the $object parameter.

    Example:

    <?php
    class myClass {
    public static     myStaticFunc($a, $b) {
    return     $a + $b;
    }
    }

    $ref = new ReflectionMethod('myClass', 'myStaticFunc');
    echo     $ref->invokeArgs(NULL, [12, 7]);
    ?>

    produces the following output:

    19
    up
    0
    cweiske at cweiske dot de
    12 years ago
    Passing arguments by reference works:
    <?php $rm->invokeArgs($object, array(&$foo, $bar)); ?>
    ＋add a note
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