The below example doesn't seem to work on a windows based machine so I use this trick instead
<?php
$aPath = explode('/',ftp_pwd($conn_id));
$sHomeDir = str_repeat('../', count($aPath) - 1);
ftp_chdir($conn_id, $sHomeDir);
?>
(PHP 4, PHP 5, PHP 7, PHP 8)
ftp_cdup — 切换到当前目录的父目录
成功时返回 true
, 或者在失败时返回 false
。
版本 | 说明 |
---|---|
8.1.0 |
现在 ftp 参数接受 FTP\Connection
实例,之前接受 resource。
|
示例 #1 ftp_cdup() 例子
<?php
// set up basic connection
$ftp = ftp_connect($ftp_server);
// login with username and password
$login_result = ftp_login($ftp, $ftp_user_name, $ftp_user_pass);
// change the current directory to html
ftp_chdir($ftp, 'html');
echo ftp_pwd($ftp); // /html
// return to the parent directory
if (ftp_cdup($ftp)) {
echo "cdup successful\n";
} else {
echo "cdup not successful\n";
}
echo ftp_pwd($ftp); // /
ftp_close($ftp);
?>
The below example doesn't seem to work on a windows based machine so I use this trick instead
<?php
$aPath = explode('/',ftp_pwd($conn_id));
$sHomeDir = str_repeat('../', count($aPath) - 1);
ftp_chdir($conn_id, $sHomeDir);
?>
ftp_cdup can only up to the parent and if you want test a directory that is not a child then you can't with ftp_cdup ;)