PHP 8.3.0 RC 6 available for testing

DateTimeImmutable::sub

(PHP 5 >= 5.5.0, PHP 7, PHP 8)

DateTimeImmutable::sub Subtracts an amount of days, months, years, hours, minutes and seconds

说明

public DateTimeImmutable::sub(DateInterval $interval): DateTimeImmutable

Returns a new DateTimeImmutable object, with the specified DateInterval object subtracted from the specified DateTimeImmutable object.

参数

interval

A DateInterval object

返回值

返回带有修改数据的新 DateTimeImmutable 对象。

错误/异常

If an unsupported operation is attempted, such as using a DateInterval object representing relative time specifications such as next weekday, a DateInvalidOperationException is thrown.

更新日志

版本 说明
8.3.0 Now throws a DateInvalidOperationException instead of a warning when an unsupported operation is attempted.

示例

示例 #1 DateTimeImmutable::sub() example

面向对象风格

<?php
$date
= new DateTimeImmutable('2000-01-20');
$newDate = $date->sub(new DateInterval('P10D'));
echo
$newDate->format('Y-m-d') . "\n";
?>

以上示例会输出:

 
2000-01-10

示例 #2 Further DateTimeImmutable::sub() examples

<?php
$date
= new DateTimeImmutable('2000-01-20');
$newDate = $date->sub(new DateInterval('PT10H30S'));
echo
$newDate->format('Y-m-d H:i:s') . "\n";

$date = new DateTimeImmutable('2000-01-20');
$newDate = $date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo
$newDate->format('Y-m-d H:i:s') . "\n";
?>

以上示例会输出:

 
2000-01-19 13:59:30
1992-08-15 19:56:58

示例 #3 Beware when subtracting months

<?php
$date
= new DateTimeImmutable('2001-04-30');
$interval = new DateInterval('P1M');

$newDate1 = $date->sub($interval);
echo
$newDate1->format('Y-m-d') . "\n";

$newDate2 = $newDate1->sub($interval);
echo
$newDate2->format('Y-m-d') . "\n";
?>

以上示例会输出:

 
2001-03-30
2001-03-02

参见

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