PHP 8.3.0 RC 6 available for testing
    Submit a Pull Request Report a Bug

    ArrayObject::__construct

    (PHP 5, PHP 7, PHP 8)

    ArrayObject::__construct — Construct a new array object

    说明

    public ArrayObject::__construct(array|object $array = [], int $flags = 0, string $iteratorClass = ArrayIterator::class)

    This constructs a new array object.

    参数

    array

    The array parameter accepts an array or an Object.

    flags

    Flags to control the behaviour of the ArrayObject object. See ArrayObject::setFlags().

    iteratorClass

    Specify the class that will be used for iteration of the ArrayObject object. The class must implement ArrayIterator.

    示例

    示例 #1 ArrayObject::__construct() example

    <?php
    $array     = array('1' => 'one',
    '2' => 'two',
    '3' => 'three');

    $arrayobject = new ArrayObject($array);

    var_dump($arrayobject);
    ?>

    以上示例会输出：

     
object(ArrayObject)#1 (3) {
  [1]=>
  string(3) "one"
  [2]=>
  string(3) "two"
  [3]=>
  string(5) "three"
}

    参见

    ＋add a note

    User Contributed Notes 4 notes

    up
    2
    german dot rumm at gmail dot com
    15 years ago
    BTW, if you need to change array later, use exchangeArray() method. Good to know when you are writing a class that extends ArrayObject()

    AFAIK, exchangeArray() doesn't return anything.

    <?php
    $a     = array('one', 'two', 'three');
    $ao = new ArrayObject($a);

    foreach (    $ao as $element) {
    echo     $element . ' '; // one two three
    }

    $b = array('four', 'five', 'six');
    $ao->exchangeArray($b); // returns null

    foreach ($ao as $element) {
    echo     $element . ' '; // four five six
    }
    ?>
    up
    -4
    ashley at nospam dot zincdigital dot com
    14 years ago
    The great confusion with this class is in its naming. ArrayObject infers it will behave as an Array and as an Object. It won't. It behaves as an array. It would better be called ArrayType. You can, with some work, get it to work both as an object and as an array, but that is up to you.
    up
    -5
    Grigori Kochanov
    17 years ago
    As Marcus explained, the flag ArrayObject::SPL_ARRAY_AS_PROPS means the array element may be used as a property if there is no conflict with visible properties.

    If there are visible properties in the class, the array element will not overwrite it's value.

    <?php
    class Rules extends ArrayObject {
    public     $len = 1;
    function     __construct($array){
    parent::__construct($array,ArrayObject::ARRAY_AS_PROPS);
    $this['len'] = 2;
    }
    }
    $x = new Rules(array(1,2));
    echo     $x->len;
    ?>
    Result: 1

    <?php
    class Rules extends ArrayObject {
    private     $len = 1;
    function     __construct($array){
    parent::__construct($array,ArrayObject::ARRAY_AS_PROPS);
    $this['len'] = 2;
    }
    }
    $x = new Rules(array(1,2));
    echo     $x->len;
    ?>
    Result: 2
    up
    -10
    agalkin at agalkin dot ru
    16 years ago
    Note that the first argument to ArrayObject::__construct, the initial array, is passed by reference. Nevertheless, modification of the array doesn't modify the object, so it may cause unexpected behaviour.

    <?php
    $array     = array('foo' => 'initial');
    $obj = new ArrayObject($array);

    // array was passed by reference:
    $obj['foo'] = 'modified';
    var_dump($array); // foo => modified

    // but it doesn't work backwards:
    $array['foo'] = 'modified_again';
    var_dump($obj); // foo => modified
    var_dump($array); // foo => modified_again
    ?>
    ＋add a note
    To Top